Question

find the smallest square number which is divisible by
9 10 12 and 15​

Answer 1

Step-by-step explanation:

But, 2 and 5 are not in pair. Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

Answer 2

Answer:

Step-by-step explanation:

Hey there!

Since, we wanted smallest perfect square number divisible by 6, 9 and 15.

So, we calculated LCM by prime factorisation.

LCM = 90

But, 2 and 5 are not in pair.

Therefore, to make it perfect square no. multiply 2 × 5 to LCM (90).

= 90 × 2 × 5

= 90 × 10

= 900

Hence,

Required smallest square no. that's divisible by 6, 9 and 15 = 900