Question

Find the smallest square
number which is divisible
by each of the numbers
6, 15 and 18​

Answer 1

Answer:

900

Step-by-step explanation:

smallest square  number which is divisible  by each of the numbers  6, 15 and 18​= LCM of 6, 15 and 18 OR Multiple of LCM

LCM of 6,15 and 18 = 90

As 90 isn't a perfect square we will do its prime factorization to make it a perfect square.

90= 2 x 3 x 3 x 5

To make 90 a perfect square we will multiply it with 2 and 5 both, as doing so will make couples in the prime factorization

90 x 2 x 5 = 900

Hence, 900 is the answer

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