Find the smallest three consecutive positive integers such that their sum is a perfect cube number.
Pls answer quickly and take pts for free
Answers
Answered by
0
Answer:
3^3 + 4^3 + 5^3 = 6^3 = 216 is smallest.
Answered by
1
Answer:
HELLOW MATE ❣️❣️
YOUR SUM SOLVED...!!
I did this by a very simple and unsophisticated but mercifully short method:
List a bunch of the smallest cubes and see which ones seem like they might be sum of three of the ones before them.
1, 8, 27, 64, 125, 216, 343, 512, 729.... aha!
1^3 + 6^3 + 8^3 = 9^3 = 729 is small,
but,
3^3 + 4^3 + 5^3 = 6^3 = 216 is smallest.
HOPE MY ANSWER HELPFUL TO YOU ❣️❣️❣️
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