Question

Find the smallest two digit number that divides 587 and 730 leaving remainder 2 in each case

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The smallest two digit number that divides 587 and 730 leaving remainder 2 in each case is 13

Given : The smallest two digit number that divides 587 and 730 leaving remainder 2 in each case

To find : The number

Tip :

HCF :

For the given two or more numbers HCF is the greatest number that divides each of the numbers

Solution :

We have to find the smallest two digit number that divides 587 and 730 leaving remainder 2 in each case

Now 587 - 2 = 585 & 730 - 2 = 728

So the required number is the smallest two digit number that divides 585 and 728 completely

We prime factorise the numbers 585 and 728

585 = 3 × 3 × 5 × 13

728 = 2 × 2 × 2 × 7 × 13

Hence the required number

= HCF of 585 and 728

= 13

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