Question

o is the centre of the circle arc abc subtends an angle of 130 degree at the centre o ab is extended up to p find angle pbc

Answer 1

,Take any point D on the circumference and join AD and DC .

∴ ∠AOC = 2 × ∠ADC

⇒ ∠ADC = 1/2 × ∠AOC = 1/2 × 130° = 65°

Now, ∠PBC = ∠ADC [exterior angle of cyclic quadrilateral]

⇒ ∠PBC = 65°

Answer 2

Answer:

<PBC=65°

Step-by-step explanation:

JOIN AD AND CD

<ADC=130/2=65° ( angle formed by a chord at centre is double the any other angle on the circle )

NOW ABCD IS A CYCLIC QUADRILATERAL,

•°•<PBC=65° ( exterior angle is equals to the opposite angle of a cyclic quadrilateral)

MAY THIS HELP YOU:)