Math, asked by vaishanvir, 10 months ago

FIND THE SMALLEST VALUE OF X FOR 3141X1 IS DIVISIABLE BY 3

Answers

Answered by mdatifnasim70mp64jpe

1

Answer:

2

Step-by-step explanation:

3+1+4+1+x+1=divisible by 3

10+x=divisible by 3

10+2=divisible by 3

x=2

Answered by sv17

2

Answer:

Answer:2

Answer:2Step-by-step explanation:

Answer:2Step-by-step explanation:3+1+4+1+x+1=divisible by 3

Answer:2Step-by-step explanation:3+1+4+1+x+1=divisible by 310+x=divisible by 3

Answer:2Step-by-step explanation:3+1+4+1+x+1=divisible by 310+x=divisible by 310+2=divisible by 3

Answer:2Step-by-step explanation:3+1+4+1+x+1=divisible by 310+x=divisible by 310+2=divisible by 3x=2

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