Question

find the smallest which when divided by 12 15 18 24 and 36 leaves no remainder​

Answer 1

Answer:

• pls mark as brainliest

Step-by-step explanation:

• the answer is 180
• usually for any number 0 can be the answer

Answer 2

Answer:

THE  smallest number which when divided by 12 15 18 24 and 36 leaves no remainder​  is 3

12 15 18 24 and 36 are all divisible by 3 .hence they will not leave any remainder except 0

the divisibility test for 3 is that the sum of the digits should add up to any multiple of 3

12

1+2=3,hence 12 is divisible

1+5=6,hence 15 is divisible

1+8=9,hence 18 is divisible

2+4=6,hence 24 is divisible

3+6=9,,hence 36 is divisible

as  3,6,9 are all multiples of 3 it is proved that 12 15 18 24 and 36 are divisible by 3

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