Question

find the smallest zero for the function h(x)=4x^2-8x-60

Answer 1

hey friend
$4 {x}^{2} - 8x - 60 = 0 \\ {x}^{2} - 2x - 15 = 0 \\ {x}^{2} - 5x + 3x - 15 = 0 \\ x(x - 5) + 3(x - 5) = 0 \\ (x + 3)( x - 5) = 0 \\ x = - 3 \\ x = 5 \\ so \: \: the \: least \: value \: of \: x = - 3$