Question

Find the solution 3x+2y=11 2x+3y=4 by elemination method

Answer 1

Hi  Sreenikethvinod here is your solution

The given equations are :

3x + 2y = 11    ....(1)     Multiply (2) by 2 and (1) by 3, we get

2x + 3y = 4   ....(2)

9x + 6y = 33    ....(3)

4x + 6y = 8    ...(4)

Subtracting (4) from (3), we get

9x − 4x = 33 − 8

⇒5x = 25

⇒x = 25/5 = 5

Now, put x = 5 in (2), we get

2×5 + 3y = 4

⇒10+3y = 4

⇒3y = 4−10

⇒3y = −6

⇒y = −63 = −2

y = −2

ANS =[ x=5,  y= (−2) ] is the solution

if u like my ans plz mark me brainliest

Answer 2

2x + 3y = 4   ....(1)     Multiply  by 2

3x + 2y = 11    ....(2)  Multiply  by 3

we get

4x + 6y = 8    ...(3)

9x + 6y = 33    ....(4)

Subtracting (3) from (4)

9x − 4x = 33 − 8

⇒5x = 25

⇒x = 25/5 = 5......................Ans

Now, put x = 5 in (1), we get

2×5 + 3y = 4

⇒10+3y = 4

⇒3y = 4−10

⇒3y = −6

⇒y = −6/3 = −2....................Ans

So, x = 5; y = −2