Find the solution by substitution method: 2x+y=21 3x+5y=49
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Given : 2x+y=21 3x+5y=49
To find : solution by substitution method
Solution:
2x + y = 21 Eq1
3x + 5y = 49 Eq2
from Eq 1
y = 21 - 2x
Substitute value of y in Eq 2
=> 3x + 5(21 - 2x) = 49
=> 3x + 105 - 10x = 49
=> -7x = 49 - 105
=> -7x = -56
=> x = 8
Substitute value of x in y = 21 - 2x
=> y = 21 - 2(8)
=> y = 21 - 16
=> y = 5
x = 8 , y = 5 is the solution
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