Find the solution by substitution method
2x+y=21
3x+5y =49
Answers
Answered by
32
Answer:-
Given:
2x + y = 21 -- equation (1)
3x + 5y = 49 -- equation (2)
From equation (1),
→ 2x + y = 21
→ y = 21 - 2x
Putting the value of y in equation (2) we get,
→ 3x + 5(21 - 2x) = 49
→ 3x + 105 - 10x = 49
→ 105 - 7x = 49
→ - 7x = 49 - 105
→ - 7x = - 56
→ x = (- 56)/(- 7)
→ x = 8
Substitute the value of x in equation (1)
→ 2x + y = 21
→ 2(8) + y = 21
→ y + 16 = 21
→ y = 21 - 16
→ y = 5
Hence, the values of x and y are 8 , 5.
Anonymous:
Nice :)
Answered by
254
- The value of x = 8
- The value of y = 5
2x + y = 21 -------------- (i)
3x + 5y = 49 ------------(ii)
2x + y = 21
=> y = 21 - 2x
3x + 5 (21 - 2x) = 49
=> 3x + 105 - 10x = 49
=> 105 - 7x = 49
=> -7x = 49 - 105
=> -7x = -56
=> x = (-56)/(-7)
=> x = 8
2x + y = 21
=> 2(8) + y = 21
=> 16 + y = 21
=> y = 21 - 16
=> y = 5
Hence,
The value of x = 8.
The value of y = 5.
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