Math, asked by KanishkSoni3061, 8 months ago

Find the solution for linear equations 3x+4y+7=0 and 5x-7y-2=0

Answers

Answered by singhshivangi232233
2

Step-by-step explanation:

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Answered by ItzLoveHunter
13

{\huge{\pink{\underline{\underline{Question}}}}}

Find the solution of equation 3x+4y+7=0 and 5x-7y-2=0

{\huge{\pink{\underline{\underline{Answer}}}}}

Lets Take {\green{\overline{\green{\underline{\blue{\boxed{\orange{\mathtt{3x + 4y + 7 = 0}}}}}}}}} ───── ( 1 )

And next {\green{\overline{\green{\underline{\blue{\boxed{\orange{\mathtt{5x - 7y - 2 = 0}}}}}}}}} ───── ( 2)

\mathrm\blue{\:Multiple \:eq(1) \:with \:5 \:and \:eq(2) \:by \:3}

➪ 5 ( 3x + 4y + 7 ) = 0 ────( from eq (1)

➪15x + 20y + 35= 0 ━━━━━━ ( 3)

➪3 ( 5x - 7y - 2 ) =0 ──── ( from eq (2)

➪ 15x - 21y - 6 = 0 ━━━━━━━ ( 4 )

EQUATE BOTH EQ (3) AND (4)

☞︎︎︎ 15x + 20y + 35

☞︎︎︎ 15x - 21y - 6

(-) ⠀(+) ⠀⠀(+) [ sign change ]

───────────

➪⠀ ⠀41y + 41 = 0

➪ ⠀⠀ ⠀ 41y = - 41

➪ ⠀⠀ ⠀⠀y = \cancel\frac{- 41}{41}

➪ y = -1

Now equate y value in equation (1)

3x + 4y + 7 = 0

3x + 4(-1) + 7 = 0

3x - 4 + 7 = 0

3x + 3 = 0

3x = 0 - 3

3x = -3

x = \cancel\frac{-3}{3}

x = -1

{\green{\overline{\green{\underline{\blue{\boxed{\orange{\mathtt{Value \:of \:x = -1 \:and \:y =-1}}}}}}}}}

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