Question

find the solution for p(x) =x²-6x+9 where x=1​

Answer 1

Step-by-step explanation:

In the given polynomial x  

2

−6x+9,

The first term is x  

2

 and its coefficient is 1.

The middle term is −6x and its coefficient is −6.

The last term is a constant term 9.

Multiply the coefficient of the first term by the constant 1×9=9.

We now find the factor of 9 whose sum equals the coefficient of the middle term, which is −6 and then factorize the polynomial x  

2

−6x+9 as shown below:

 

x  

2

−6x+9

=x  

2

−3x−3x+9

=x(x−3)−3(x−3)

=(x−3)(x−3)

Therefore, x  

2

−6x+9=(x−3)(x−3).

so the zero of the polynomial is 3.

Answer 2

Answer:

p(x)=x²-6x+9

=(1)²-6(1)+9

=1-6+9

=10-6

=4 Ans

Step-by-step explanation:

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