Question

find the solution for the pair of linear equation 4x+5y=1,5x-3y+8=0 by graphical method​

Answer 1

Answer ;

4x + 5y = 1-----(1) , 5x - 3y + 8 = 0-------(2)

Step-by-step explanation:

(01) Put x = 0 in - - - - (1) (02) put x = 1 in - - (1)

4x + 5y = 1 4(1) + 5y = 1

4(0) + 5y = 1 4 + 5y = 1

0 + 5y = 1 5y = 1 - 4

5y = 1 - 0 5y = - 3

y = 1/5 y = - 3/5

y = 0.2 y = - 0.6

(03) put x = 2 in - - - -(1) (04) put x = 3 in - - (2)

4(2) + 5y = 1 4(3) + 5y =1

8 + 5y = 1 12 + 5y = 1

5y = 1 - 8 5y = 1 - 12

5y = - 7 5y = - 11

y = - 7/5 y = - 11/5

y = - - 1.4. y = - 2.2

Now.

Again.

(01) put x = 0 in - - - - (2) (02) put x = 1 in - - (2)

5x - 3y + 8 = 0 5(1) - 3y + 8 = 0

5(0) - 3y + 8 = 0 5 - 3y + 8 = 0

0 - 3y + 8 = 0 13 - 3y = 0

-3y = -8 - 3y = - 13

y = 8/3 y = 13/3

y = 2.6 y = 4.3

(03) put x = 2 in - - - - (2) (03) put x = 3 in - - (2)

5(2) - 3y + 8 = 0 5(3) - 3y + 8 = 0

10 - 3y + 8 = 0 15 - 3y + 8 = 0

18 - 3y = 0 23 - 3y = 0

-3y = - 18 - 3y = - 23

y = 18/3 y = 23/3

y = 6 y = 7.0

Answer 2

The solution for the pair of linear equation 4x+5y=1, 5x-3y+8=0 is x = -1, y = 1

Step-by-step explanation:

Given linear equations

$L_1: 4x+5y=1$

$L_2:5x-3y+8=0$

Which are the equations of a line

In order to draw the graph of a line we only need two points satisfying the equation of the line

The graphs of lines $L_1$ and $L_2$ are drawn

From graph it is clear that the lines intersect at point A

The coordinates of point A are (-1,1)

Therefore, the solution of the pair of linear equations is

x = -1, y = 1

Hope this answer is helpful.

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