Question

find the solution for this?​

Answer 1

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Answer 2

Answer:

$a1 = {s}^{2}(1) and \: a2 = {s}^{2} (2) \\ a1 + a2 = 850 \\ {s}^{2} (1) + {s}^{2} (2) = 850 \\ and \: \\ p1 - p2 = 40 \\ 4s1 - 4s2 = 40 \\ s1 - s2 = 10 \\ s1 = 10 + s2 \\ now \\ {(10 + s2)}^{2} + {s}^{2} (2) = 850 \\ 100 + 20s2 + {s}^{2} (2) + {s}^{2}(2) = 850 \\ {s}^{2} (2) + 10s2 + 50 = 425 \\ {s}^{2} (2) + 10s2 - 375 = 0 \\ d = {b}^{2} - 4ac \\ = 100 + 4 \times 375 \\ = 100 + 1500 \\ = 1600 \\ {s}(2) = \frac{ - b + \sqrt{d} }{2a} or \: {s} (2) = \frac{ - b - \sqrt{d} }{2a} \\ = \frac{ - 10 + \sqrt{1600} }{2} or \: = \frac{ - 10 - \sqrt{1600} }{2} \\ = \frac{ - 10 + 40}{2} \: = \frac{ - 10 - 40}{2} \\ = 15 \: or \: = - 25 \\ for \: s2 = 15 \\ s1 = 25 \\ for \: s2 = - 25 \\ s1 = - 15$