Math, asked by Subhushanmukh, 4 months ago

find the solution of (D²+4D+3)y=0.

Answers

Answered by shrutirupa

2

Answer:

D=-1 or D=-3 or y=0

(d^2+4d+3)y=0

y=0 or d^2+4d+3=0

d^2+4d+3=0

d^2+d+3d+3=0

d(d+1)3(d+1)=0

(d+3)(d+1)=0

d=-3 or d=-1

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