find the solution of (D²+4D+3)y=0.
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D=-1 or D=-3 or y=0
(d^2+4d+3)y=0
y=0 or d^2+4d+3=0
d^2+4d+3=0
d^2+d+3d+3=0
d(d+1)3(d+1)=0
(d+3)(d+1)=0
d=-3 or d=-1
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