Two wires A and B are of the same length. The diameters are in the ratio 1 : 2 and the Youngs modulus are in ratio 2 : 1. if they are pulled by the same force, then their elongations will be in ratio
(a) 4 : 1
(b) 1 : 4
(c) 1 : 2
(d) 2 : 1
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Answer:
we khow Y= F. L/A.∆l, so ∆l=(F.L)/(Y.A),
here A is the area.so ∆l1/∆l2=2:1
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