Question

Find the solution of the equation √5x-√7y=0 and √3y+√13x=0

Answer 1

$a1 = \sqrt{5} \: b1= - \sqrt{7} \: c1 = 0 \\ a2 = \sqrt{13} \: b2 = - \sqrt{7} \: c2 = 0 \\ x = \frac{b1c2 - b2c1}{a1b2 - a2b1} \\ x = \frac{ - \sqrt{7} \times 0 - ( - \sqrt{3} ) \times 0 }{ \sqrt{5} \times - \sqrt{3} - \sqrt{13} \times ( - \sqrt{7) } } \\ x = \frac{0}{ - \sqrt{5} \sqrt{3} + \sqrt{13} \sqrt{7 } } \\ x = 0$

x=0

similarly if we put the formula for y we get y=0