Question

find the solution of the following:

Answer 1

Answer:

The weather is forecasted to be patchy rain possible with daytime temperature reaching 28 °c. Night time temperature are expected to be 25 °c.

Step-by-step explanation:

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Answer 2

Answer:

6cm

Step-by-step explanation:

We have

Side=6cm

Height=4cm

Areaofa∥gm=base×height

Areaofa∥gm=base×height=6×4

Areaofa∥gm=base×height=6×4=24cm

Areaofa∥gm=base×height=6×4=24cm 2

Areaofa∥gm=base×height=6×4=24cm 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus=

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24=

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 =

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 8

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2 ∴d

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2 ∴d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2 ∴d 2

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2 ∴d 2 =6

Areaofa∥gm=base×height=6×4=24cm 2 Areaofarhombus= 21 ×d 1 ×d 2 ⇒24= 21 ×8×d 2 ⇒d 2 = 824×2 ∴d 2 =6Hence,other length is6cm.

is6cm.

is6cm.