Question

find the solution of the linear equation 8x + 5y + 32 = 0 which represents a point in 2 quadrant ​

Answer 1

Given: The linear equation 8x + 5y + 32 = 0

To find: The solution of linear equation that represents a point in 2nd quadrant.

Solution:

• Now we know that in 2nd Quadrant  x is always negative & y is always positive.

• So we will take magnitude, we get:

                   8(-x)  + 5y  + 32  = 0

                   5y  =  8x  - 32

• Now lets consider y > 0   if  x   >  4

• Assume that x  =  5, then we get:

                   5y = 40 - 32

                   5y = 8

                   y = 1.6

Answer:

                 So, when x = -5 then y = 1.6  is the solution in 2nd Quadrant.

Answer 2

Answer:

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