Question

Find the solution of the quadratic equation by factorization method.


$\sqrt{2x {}^{2} } \: + \: 7x \: + \sqrt[5]{2} = \: 0$
​

Answer 1

Answer:

Given,

2

x

2

+7x+5

2

=0

or,

2

x

2

+2x+5x+5

2

=0

or, x

2

(x+

2

)+5(x+

2

)=0

or, (x

2

+5)(x+

2

)=0

⇒x=−

2

5

,−

2

.

Answer 2

$\huge\sf\red{\colorbox{orange}{Solution \ of \ the \ Quadratic \ Equation }}\\\huge\sf\red{\colorbox{orange}{ by \ Factorization \ method :-}}$

$\sf{\blue{ \sqrt{2}x^{2} + 7x + 5\sqrt{2} = 0 }}$

$\sf{\implies \sqrt{2}x^{2} + 2x + 5x + 5\sqrt{2} = 0}$

$\sf{\implies \sqrt{2}x ( x + \sqrt{2} ) \ 5( x + \sqrt{2} ) = 0 }$

$\sf{\implies ( x + \sqrt{2} ) ( \sqrt{2}x + 5) = 0}$

$\huge{\bold{\implies x = \sqrt{-2} , \frac{-5}{\sqrt{2} } }$

Hope it helps :)

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