Question

Find the solution set of the following inequation and represent it on the number line:(x/2)+3<=(x/3)+4< 4x-7, x belongs to real number ​

Answer 1

Answer:

there is no solution for this question

$\frac{x + 2}{3 } \leqslant \frac{x + 3}{4} \\ after \: cross \: multipying \: \: we \: get \: x \leqslant 1 \\ \\ \frac{x + 3}{4} < 4x - 7 \\ after \: multiplying \: we \: get \: x > \frac{31}{5}$

Step-by-step explanation:

so no soln for this question