find the solution ? this question is from progressions.
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Step-by-step explanation:
15th term=a+14d
a=2 , d=3
So 2+14×3
2+42=44
15th term=44
Sum of first 10 terms=n/2[2a+(n-1)d]
=10/2[4+(9)3]
=5×31
= 155
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