Math, asked by Anonymous, 9 months ago

find the solutions of:

1:a^6-b^6

2:a^12-1

Answers

Answered by Itzraisingstar
2

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Step-by-step explanation:

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1:a^6-b^6:

⇒(a²)³-(b²)³,

⇒(a²-b²)(a^4+a²b²+b^4),

⇒(a-b)(a+b)(a^4+a²b²+b^4),

⇒(a-b)(a+b)(a²+ab+b²)(a²-ab+b²) is the correct answer.✔✔✔

2:a^12-1:

⇒(a^4)³-1,

⇒(a^4-1)(a^8+a^4+1),

⇒(a²-1)(a²+1)(a^8+a^4+1),

⇒(a+1)(a-1)(a²+1)(a^8+a^4+1),

⇒(a+1)(a-1)(a²+1)((a^4)²+2(a^4)(1)+1-a),

⇒(a+1)(a-1)(a²+1)((a^4+1)²-a^4),

⇒(a+1)(a-1)(a²+1)(a^4-a²+1)(a^4+a²+1),

⇒(a+1)(a-1)(a²+1)(a^4-a²+1)(a^4+a²+1)(a²-a+1).

Hope it helps you.

Answered by Anonymous
0

Answer:

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