Find the speed of a train which leaves Secundrabad at 7 p.m. and reaches Bhopaletes
day at 6am It stops for 1 hour on the way. The distance between Secundrabad and Bhopal
6710 km. Also find the average speed correct to one place of decimal
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Answer:
mark me brainlist if it's correct
Step-by-step explanation:
Distance travelled = 710 km
Time taken = 10 hrs
We know Distance = speed * time
Speed = Distance /time
= 710/10 = 71 km/hr
Average speed = 71 km/hr
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