Question

Find the sq•root of ( x2+4x+4)(x2+6x+9)

Answer 1

Four solutions were found :

 x = 9

 x = -1

 x =(5-√61)/2=-1.405

 x =(5+√61)/2= 6.405

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

      ((x^2-6*x-9)/x)-(((x^2-4*x-9)/(x^2-6*x-9)))=0 

Step by step solution :

Step  1  :

x2 - 4x - 9 Simplify ——————————— x2 - 6x - 9

Trying to factor by splitting the middle term

 1.1     Factoring  x2 - 4x - 9 

The first term is,  x2  its coefficient is  1 .
The middle term is,  -4x  its coefficient is  -4 .
The last term, "the constant", is  -9 

Step-1 : Multiply the coefficient of the first term by the constant   1 • -9 = -9 

Step-2 : Find two factors of  -9  whose sum equals the coefficient of the middle term, which is   -4 .

     -9   +   1   =   -8     -3   +   3   =   0     -1   +   9   =   8


Observation : No two such factors can be found !! 
Conclusion : Trinomial can not be factored