find the square 78 using long identity
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Answer:
(78)^2=
(80-2)^2
we know that (a-b)^2=a^2-2ab+b^2
Similarly,
(80)^2-2*80*2+(2)^2
80*80-2*80*2+2*2
6400-320+4
6404-320=
6084
Ans=6084
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