Question

find the square by using identities:
2/3m+3/2n

Answer 1

Hello,
In the question we have 2 terms
On squaring we will get the formulae of (a+b) ²

So, (2/3m + 3/2n)²
We know that (a+b) ² = a² +b² +2ab
So,
(2/3m+3/2n)² = (2/3m)² + (3/2n)² + 2(2/3m)(3/2n)
= 4/9m² + 9/4n² + 2mn

Hope this will be helping you.

WARM REGARDS
Sahil khirwal.

Answer 2

$\bold {(\frac{2}{3}m+\frac{3}{2}n)^2=\frac{4}{9}m^2+\frac{9}{4}n^2+2mn}$

Step-by-step explanation:

We have to find the square of$(\frac{2}{3}m+\frac{3}{2}n)$.

By using Identity,$\bold {(a+b)^2 = a^2+b^2+2ab}$

$(\frac{2}{3}m+\frac{3}{2}n)^2$

= $(\frac{2}{3}m)^2+(\frac{3}{2}n)^2+2(\frac{2}{3}m\times \frac{3}{2}n)$

=$\frac{4}{9}m^2+\frac{9}{4}n^2+2mn$

$\bold {Hence,(\frac{2}{3}m+\frac{3}{2}n)^2=\frac{4}{9}m^2+\frac{9}{4}n^2+2mn}$