Question

find the square of 11 using distributive law​

Answer 1

$(11) {}^{2} = (10 + 1) {}^{2}$

$(a + b) {}^{2} = a {}^{2} + b {}^{2} + 2 ab$

A=10 and b=1

$10 {}^{2} + 1 {}^{2} + 2(10)(1)$

100+1+20

121