the sum of the digits of a two digit number is 8.if the digit are reversed.the new number increase by 18.find the number
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let the digits are x and y where x is on tens place and y is on unit place
x + y =8.....(1)
if digits are reversed then
10y + x = 10x+y +18
9y-9x = 18
y-x = 2.....(2)
by adding (1) and (2)
x+y+y-x = 8+2
2y = 10
y = 5
put this value in (1)
x+y=8
x+5 = 8
x=8-5 =3
x = 3 and y= 5
hence the two digit number is= 35
i hope it will help u
NeelamG:
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