find the square of (2×+3y)
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5
Find: (2x + 3y)²
By using the identity of (a + b)² = a² + 2ab + b² we get:
=> (2x + 3y)²
=> (2x)² +2(2x)(3y) + (3y)²
=> 4x² + 12xy + 9y²
Hence, 4x² + 12xy + 9y² is your answer
Answered by
0
Answer:
(2x+3y)*(2x+3y)
4x^2+12xy+9y^2
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