find the square of (2×+3y)
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Answered by
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Answer:
(2x+3y)^2
= (2x)^2 + 2(2x)(3y) + (3y)^2
= 4x^2 + 12xy + 9y^2
Answered by
0
Answer:
(2x + 3y)
=(2x + 3y)²
=(2x)² + (3y)² + (2)(2x)(3y)
=4x² + 9y² + 12xy
So the right answer is
4x² + 9y² + 12xy
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