Question

Find the square of 29 using a formula a-b square = a square + 2 a b + b square

Answer 1

$\huge\mathcal{Answer:}$

We have to find square of 29 using identity :

(a-b)^2 = a^2 - 2ab + b^2

If we will break 29 in form of (a-b)^2

Then [30 - 1] in which a = 30 and b = 1

$(30 - 1) ^{2}$

$( {30})^{2} - 2 \times 30 \times 1 + (1 )^{2}$

$900 - 60 + 1$

$901 - 60$

$841$

Hence,

$({29})^{2} = 841$

Answer 2

Answer:

841

Step-by-step explanation:

29 = (20+9)

a^2 + b^2 + 2ab

= 20^2 + 9^2 + 2 (20) (9)

= 400 + 81 + 180 x 2

= 481 + 360

= 841