Math, asked by akku4363, 10 months ago

find the square of (3z-2/3)^2​

Answers

Answered by dhrugupt
1

Answer:

Step-by-step explanation

(3z - 2/3)^2

= 9z^2 + 4/9 - 4

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Answered by Anonymous
13

Answer:

 {(3z -  \frac{2}{3}) }^{2}  =  {3z}^{2}  - 2 \times 3z \times  \frac{2}{3}  +  { ( \frac{2}{3}) }^{2}  \\ 9 {z}^{2}  - 4z +  \frac{4}{9}

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