Question

Find the square of.
√5-2​

Answer 1

$\huge{\underline{\sf Required\:Solution:-}}$

$\\ \tt{:}\longrightarrow (\sqrt{5}-2)^2$

$\\ \tt{:}\longrightarrow (\sqrt{5})^2-2(\sqrt{5})(2)+(2)^2$

$\\ \tt{:}\longrightarrow 5-4\sqrt{5}+4$

$\\ \tt{:}\longrightarrow 5+4-4\sqrt{5}$

$\\ \tt{:}\longrightarrow 9-4\sqrt{5}$

Used identity :-

$\boxed{\sf (a-b)^2=a^2-2ab+b^2}$