Math, asked by gauravgiri7303, 5 months ago

find the square of 7+2root10​

Answers

Answered by madhulika7
0

Answer:

Square root of 7 + 2√10

=√(7+2√10)

= √[5+2+2×√(5×2)] we can write 7=5+2 & 2√10 =2×√(5×2)

So by using (a+b)^2 = a^2+b^2 +2ab

= √[ (√5)^2 +(√2)^2+√(2×5)]

= √[(√5+√2)^2]

= √5+√2 because √(a^2) = a

I HOPE THIS WILL HELP

Answered by Anonymous
4

\huge\boxed{\fcolorbox{aqua}{lime}{answer☆}}

−−√−−−−−−−−√7+210

7+25⋅2−−−√−−−−−−−−−√7+25⋅2

Apply the rule ab−−√=a−−√b√ab=ab:

⟹7+25–√2–√−−−−−−−−−√⟹7+252

Rewrite 77 as 5+25+2:

⟹5+2+25–√2–√−−−−−−−−−−−−√⟹5+2+252

Remember that a+b=b+aa+b=b+a.

⟹5+25–√2–√+2−−−−−−−−−−−−√⟹5+252+2

Similar questions