find the square of 7+2root10
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Answer:
Square root of 7 + 2√10
=√(7+2√10)
= √[5+2+2×√(5×2)] we can write 7=5+2 & 2√10 =2×√(5×2)
So by using (a+b)^2 = a^2+b^2 +2ab
= √[ (√5)^2 +(√2)^2+√(2×5)]
= √[(√5+√2)^2]
= √5+√2 because √(a^2) = a
I HOPE THIS WILL HELP
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−−√−−−−−−−−√7+210
7+25⋅2−−−√−−−−−−−−−√7+25⋅2
Apply the rule ab−−√=a−−√b√ab=ab:
⟹7+25–√2–√−−−−−−−−−√⟹7+252
Rewrite 77 as 5+25+2:
⟹5+2+25–√2–√−−−−−−−−−−−−√⟹5+2+252
Remember that a+b=b+aa+b=b+a.
⟹5+25–√2–√+2−−−−−−−−−−−−√⟹5+252+2
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