Question

Find the square of √9+40i +√9-40i

Answer 1

Answer:

60

Step-by-step explanation:

${( \sqrt{9 + 40i} + \sqrt{9 - 40i} )}^{2} = 9 + 40i + 9 - 40i + 2 \times \sqrt{ {9}^{2} - {40i}^{2} } \\ = 18 + \sqrt{81 - ( - 1600)} \\ = 1 8+ \sqrt{1681} \\ = 18 + 41 \\ = 60$