Question

Find the square of 99 using the identity
(a - b)2 = a2 - 2ab + b2​

Answer 1

$\bf\large\underline\blue{Question:-}$

• Find the square of 99 using the identity $(a-b)^{2}=a^{2}+b^{2}-2ab$

$\bf\large\underline\blue{Solution:-}$

${99}^{2}$

Can be written as,

${(100 - 1)}^{2}$

Now, we can apply the identity.

$\bf\underline\blue{Therefote:-}$

$= {(100 - 1)}^{2}$

$= {100}^{2} + {1}^{2} - 2 \times 100 \times 1$

$= 10000 + 1 - 200$

$= 10001 - 200$

$= 9801$

$\bf\large\underline\blue{Answer:-}$

• ${99}^{2} = 9801$

Answer 2

Answer:9801

Step-by-step explanation:

(100 - 1)²= 100² - 2 × 100 × 1 + -1²

             = 10000 - 200 + 1

              = 9801

hope this answer helps u

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