Question

find the square of
$4x^{2} - 1by4x$
​

Answer 1

Step-by-step explanation:

$(4x^{2}- \frac{1}{4x} )^{2}$       [∵$(a - b)^{2} = a^{2} - 2ab+b^{2}$]

= $(4x^{2} )^{2} - 2 * 4x^{2} * \frac{1}{4x}+ (\frac{1}{4x} )^{2}$

= $16x^{4} - 2x + \frac{1}{16x^{2} }$ (Ans)