Question

Find the square of the following
a)93
b)23/35
c)11/17
d)8a

Answer 1

a)= (93)^2 = 93*93= 8649

b)= (23/35)^2 = (23/35)(23/35)= (529/1225)=0.431836735

c)= (11/17)^2 = (11/17)(11/17)= (121/289)= 0.418685121

d)= (8a)^2 = (8a)(8a)= 64a^2


Hope it will help you

please mark it as brainiest

Answer 2

see I have a awesome trick to find any 2digit square easily.
method called squaring by Vedic math
use Formula
$({a}^{2} ) \:( 2ab) \: ( {b}^{2} )$
where 'a' is first digit of 2-digited no, b is last or second digit of 2-digit no, and 2ab means product of last and first no with 2.
and then combine
e.g. square of 93
${9}^{2} \: \: \: \: 2 \times 9 \times 3 \: \: \: \: \: {3}^{2}$
81. 54. 9
86. 4. 9
8649 (ans)

method II
step1:- square of any nos ends with 5
divide the no into 2 parts such that last part contain only 5 and first part contain rest nos
step2:- multiply the 1st part with its successor
Step 3:- find square of 5 i.e. 25
combine both them get the answer
e.g. square of 35
3. 5
3×4. 5 square
12. 25
1225 (ans)
I hope rest part u can solve it by this method