Question

Find the square of the following numbers using the identity : (a-b) ² = a²-2ab +b² :- i) 395 ,ii) 99

Answer 1

ii) 99² = (100-1)(100-1)
Which = (100-1)²
= 100² - 2*100*1+(1)²
=10000-200+1
9801.
Hope it helps!

Answer 2

⭐⭐Hello friend..Ur answer is here⤵⤵

⚫ 395

➡(400-5)^2

➡(400)^2-2×400×5+(5)^2

➡160000-4000+25

➡156025

⚫99

➡(100-1)^2

➡ 100^2-2×100×1+1^2

➡ 10000-200+1

➡ 9801

I HOPE IT IS HELPFUL TO YOU ☺