Question

Find the square of the following using the identity ( a+b)=a2+2ab+b2.a)99

Answer 1

Answer:

the square of 99 is 10201

Step-by-step explanation:

99 = 100-1

$99^{2}=(100-1)^{2}$

$\\(100-1)^{2} = (100)^{2}+2*(100)*(1)\\\\=10000+201+1\\\\=10201$

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Answer 2

${99}^{2}$

$= ( {100 - 1})^{2}$

$= (100) ^{2} - 2( 100)(1) + {(1)}^{2}$

$using \: identity \: (a - b )^{2} = {a}^{2} - 2ab + {b}^{2}$

$= 10000 - 200 + 1$

$= 9801$

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