find the square root of 1296 by using tens and ones method
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√12961296
Split the radicand into pairs of digits.
√11229966
Determine the largest integer whose squareis less than or equal to 1212.
33√11229966
Square the value above the line and place it under the term like in a long divisionproblem.
33√1122996699
Subtract 99 from 1212 to get 33.
33√112299669933
Bring down the next two digits of the radicand.
33√1122996699339966
Double the number above the radicand (2⋅3=6)(2⋅3=6) and write it down followed by a blank space (n)(n), inside parentheses. Then, multiply it by nn.
33√1122996699339966 (66nn)·nn
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