Question

find the square root of 2304 and 1764 and hence find the value of√ 0.2304+√0.1764/√0.2304+√0.1764

Answer 1

Root of 2304=48

Root of 1764 =42

[Root of 0.23 04 + root of 0.1764] /[root of 0.2304 - root of 0.1764]

(0.48+0.42)/(0.48-0.42)

0.9/0.06

15

Hope it helps u....

Answer 2

The value of the equation is 1.

Given,

Number 1 = 2304

Number 2 = 1764

To Find,

√0.2304+√0.1764/√0.2304+√0.1764 =?

Solution,

The expression is √0.2304+√0.1764/√0.2304+√0.1764

Let x = √0.2304+√0.1764

We know the square root of  2304 and 1764 is

√2304 = √(2*2*2*2*2*2*2*2*3*3) = √(2*2*2*3)² = 48

√1764 = √(2*2*3*3*7*7) = √(2*3*7)² = 42

So, putting the value of numbers in x, we get

$x = \sqrt{0.2304} + \sqrt{0.1764} \\x = \sqrt{\frac{2304}{10000} } + \sqrt{\frac{1764}{10000} } \\x = \frac{48}{100} + \frac{42}{100} \\x = 0.48 + 0.42\\x = 0.9$

In the equation, we have

√0.2304+√0.1764/√0.2304+√0.1764 = x / x = 0.9 / 0.9

√0.2304+√0.1764/√0.2304+√0.1764 = 1

Hence, the value of √0.2304+√0.1764/√0.2304+√0.1764 is 1.