Question

Find the square root of 3-4i.

Answer 1

$3 - 4i\\ = {(2)}^{2} + {( i) }^{2} - 2 \times 2 \times i \\ = {(2 - i) }^{2}$
$\sqrt{ {(2 - i) }^{2} } \\ = 2 -i$

Answer 2

Answer:

hey mate ❤️☺️....here is the answer....

3-4i

=4-1-4i

=2^2+i^2-2.2.i

=(2-i)^2

•°•√(3-4i)=+(2-i)

Step-by-step explanation:

Hope this help u ☺️....mark as brainliest☺️✌️