Question

find the square root of 4a^2+b^2+c^2+4ab-2bc-4ac

Answer 1

Check the attachment

Answer 2

Answer:

(2a+b-c)

Explanation:

____________________

We know the algebraic identity:

x²+y²+z²+2xy+2yz+2zx

= (x+y+z)²

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Here, given

4a²+b²+c²+4ab-2bc-4ac

= (2a)²+b²+(-c)²+2*(2a)*b+2*b*(-c)+2*(-c)*(2a)

= (2a+b-c)²

Now,

Square root of 4a²+b²+c²+4ab-2bc-4ac

= $\sqrt{(2a+b-c)^{2}}$

= $ (2a+b-c)$

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