Math, asked by krishna464, 1 year ago

find the square root of 64 by repeated subtraction method

Answers

Answered by StarrySoul
79

Hello!

Square root of 64 =

64-1 = 63

63-3 = 60

60-5 = 55

55-7 = 48

48-9 = 39

39-11 = 28

28-13 = 15

15-15 = 0

Hence,

 \sqrt{64}  = 8

Hope this helps

Answered by priyadarshinibhowal2
0

The square root of 64 is 8.

  • The opposite of squaring an integer is finding its square root. The result of multiplying a number by itself yields its square value, while the square root of a number can be found by looking for a number that, when squared, yields the original value.
  • Every number has two square roots, one of a positive value and one of a negative value, because the square of any number is always a positive number.

Here, according to the given information, we are given that,

We need to find the square root of 64 using repeated subtraction method.

Now, subtracting 1 from 64, we get 63.

Now subtracting consequent odd numbers from the consecutive differences obtained, we get,

64-1=63.\\63-3 = 60.\\60-5 = 55.\\55-7=48.\\48-9=39.\\39-11 = 28.\\28 - 13 = 15.\\15-15=0.

We will proceed no further since we have obtained 0 as the last difference.

The total number of differences to find 0 as the final difference is 8.

Hence, the square root of 64 is 8.

Learn more here

https://brainly.in/question/1059189

#SPJ3

Similar questions