find the square root of 7-4√3
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Answered by
13
Answer:
Step-by-step explanation:To solve this kind of question, first assume its square root.
Let the square root of (7 - 4√3) be (a-√b)
So we can say " (a -√b)^2 = 7 - 4√3 "
(a -√b)^2 = a^2 + b - 2a√b
Thus a^2 + b - 2a√b = 7 - 4√3
Or
(a^2 + b) = 7. And
2a√b = 4√3
(Two equation, two variable=>can be solved)
You can see clearly 2a = 4 => a =2
And b=3
Thus square root of 7-4√3 is (a-√b) or (2 - √3)
hope d answer is correect plzz follow me
sujaybk11:
its correct know
Answered by
9
approx -4. 28 is the square root of 7 -4√3
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