Question

Find the square root of 8 +6i. ​

Answer 1

Answer:

Let the square root be x+iy

⇒(x+iy)=−8−6i

Taking square on both the side

⇒x2−y2+2xyi=−8−6i

By comparing we get.

⇒x2−y2=8 and 2xy=−6

⇒xy=−3

⇒y=x−3

⇒x2−(x−3)2=−8

⇒x2−x29=−8

⇒x4−9=−8x2

⇒x4+8x2−9=0

⇒x4+9x2−x2−9=0

⇒x2(x2−1)+9(x2−1)=0

⇒(

Answer 2

Step-by-step explanation:

square root of 8+6i =3+i