find the square root of -8-6i
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Answered by
68
LET √(-8-6i)=x+iy
SQUARING BOTH SIDES AND FIND VALUES OF X AND Y
-8-6i=(x+iy)²
we get x²-y²=(-8) and 2xy=(-6) by equating real and imaginary parts
x=(-3)÷y
THE ANSWER IS x+iy=+(1+i3) or -(1+i3)
SQUARING BOTH SIDES AND FIND VALUES OF X AND Y
-8-6i=(x+iy)²
we get x²-y²=(-8) and 2xy=(-6) by equating real and imaginary parts
x=(-3)÷y
THE ANSWER IS x+iy=+(1+i3) or -(1+i3)
Answered by
26
square root of -8-6i
= √(-1)(8+6)√(-1). --------(i=iota)
= (√14 ) × i^3/4
hope this helped ....... !
= √(-1)(8+6)√(-1). --------(i=iota)
= (√14 ) × i^3/4
hope this helped ....... !
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